|
[ Information | Background | The CyberTeaser | Quantum News | Miscellaneous Stuff ] Solution to CyberTeaser B271Yes, its possible. For example, consider the numbers 1, 2, 3, 4, 5, and x. Then x can be found from the equation 1 + 2 + 3 + 4 + 5 + x = 1 × 2 × 3 × 4 × 5 × x. In this case, x = 15/119. CyberTeaser Archive
Copyright © 1999 National Science Teachers
Association |