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Solution to CyberTeaser B258

RectanglesConsider the four rectangles at the upper left corner (see the figure). The area of one of them is not known. Let’s find it. We can see that the ratio of the areas of rectangles 1 and 2 is the same as the ratio of the areas of rectangles 3 and 4. Therefore, the area of rectangle 3 is 6. Reasoning in the same way, we can successively find the areas of the reactangles above and diagonal that runs from the upper left to the lower right. As a result, we find that the area of the desired rectangle is 24.

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